Jul 27, 2022

How To Calculate Aeration Volume ?

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Contents
 

1.Method One: Calculate According To The Air-Water Ratio

 

2.Method Two: Calculated by removing 1 kg of BOD and 1.5 kg of O2 

 

3.Methoa Three: Calculate the aeration intensity accordina to the unit tank area

 

4.Method 4: Calculate according to the number of aeration heads

 

Known to:

 

(1) Water flow: 46m3/h

 

(2) COD: 1200mg/L

 

(3) No data for BOD,here we assume BOD=0.5*COD=600mg/L

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Four Calculate Methods

 

Method 1

 

Calculate According To The Air-Water Ratio

Contact oxidation Tank 15:1,so the air volume is: 15*46=690m3/h

Activated sludge tank is 10:1, then the air volume is: 10*46=460 m3/h

The adjustment tank is 5:1, then the air volume is: 5*46=230 m3/h

The total air volume is: 690+460+230=1380 m3/h=23 m3/min

 

Method 2

 

Calculated by removing 1 kg of BOD and 1.5 kg of O2

The removal amount of BOD per hour is 0.6kg/m3*1100m3/d÷24=27.5kgBOD/h

Oxygen demand: 27.5*1.5=41.25kgO2

The weight of oxygen in the air is 0.233kg O2/kg air,

Then the required air volume is: 41.25 kgO2÷0.233 O2/kg air=177.04 kg of air

The density of air is 1.293 kg/m3

Then the air volume is: 177.04kg÷1.293 kg/m3=136.92 m3

The oxygen utilization rate of the microporous aeration head is 20%,

Then the actual air demand is: 136.92 m3÷0.2=684.6m3=11.41m3/min

 

 

 

Method 3

 

Calculate the aeration intensity according to the unit tank area

The aeration intensity is generally 10-20 m3/m2h, taking the middle value, the aeration intensity is 15 m3/m2h

The total area of the contact oxidation tank and activated sludge tank is: 125.4 m2

Then the air volume is: 125.4*15=1881 m3/h=31.35 m3/min

The aeration intensity of the regulating tank is 3m3/m2h, and the area is 120m2, the air volume is 3*120=360m3/h=6m3/min

A total of 37.35 m3/min is required

 

Method 4

 

Calculate according to the number of aeration heads

Calculate the pool capacity according to the residence time, and then calculate that a total of 350 aeration heads are required, and the air demand is 3 m3/h.

Then the total required air is 350×3=1050 m3/h=17.5 m3/min

In addition, the gas demand of the regulating tank is 6 m3/min,

Total required air: 23.5 m3/min

 
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