Description
Technical Parameters
Sewage Treatment Air Flow Calculation
The following is Aquasust for you to sort out the correct way to calculate the amount of aeration：
- Blue block is the design datameter : be filled in
- Brown: calculate process data
- greener : last result for your process
1.Sewage Treatment--Parameter
| 1.Sewage Treatment--Parameter | |||
| Water volume m3/h | COD(mg/l) | BOD | |
| 46 | 1200 | No data：BOD=0.5×COD=600mg/L | 600 |
2. Calculation by Gas-Water Ratio
| 2. Calculation by Gas-Water Ratio | |||
| Contact oxidation tank | 15:01:00 | 15×46=690m3/h | 690 |
| Activated sludge tank | 10:01:00 | 10×46=460m3/h | 460 |
| Conditioning tank | 5:01:00 | 5×46=230m3/h | 230 |
| Total air volume | 690+460+230=1380m3/h=23m3/min | 1380 | |
3.According to Remove 1kgBOD Need 1.5 Oxygen
| 3.According to Remove 1kg BOD Need 1.5 Oxygen | ||
| The amount of BOD removed per hour is: | 600mg/L×46m3/h=27.6kg | 27.6 |
| Oxygen demand | 27.6×1.5=41.4kg/h | 41.4 |
| Weight of oxygen in air | 0.233 kg O2/kgAir | |
| Density of air: | 1.293kg/m3 | |
| Then the amount of air required: | 41.25÷0.233=177.7kg/h | 17.68 |
| Then the volume of air | 177.04÷1.293=137.4m3/h | 137.42 |
| Set the microporous aeration head oxygen utilization rate of 20% | ||
| Then the actual amount of air required | 137.4÷0.2=687m3/h=11.45m3/min | 11.45 |
4.According to The Unit Pool Area Aeration Intensity Calculation
| 4.According to The Unit Pool Area Aeration Intensity Calculation | |||
| Aeration intensity generally 10-20m3/m2.h | |||
| Aerobic pool to take the middle value of 15m3/m2.h | 15 | 125 | |
| Adjustment pool take 5m3/m2.h | 3 | 120 | |
| Contact oxidation and activated sludge tank area | 0.25 | ||
| Then the aerobic tank requires air volume | 125×15=1875m3/h=31.25m3/min | ||
| Then the air volume required for regulating tank | |||
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